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本帖最后由 hi_yjs 于 2013-1-25 21:14 编辑
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$ B7 K. @% D. i! b1 P/ w最近用热敏电阻做个温度计。
1 o7 I' D5 R5 f F# G# q( s1 T大家都知道,热敏电阻阻值随温度是非线性变化的,而且规格书也只是跳跃地给出部分对应值。
9 j- n, ~# f! N& _请问该如何写出较高精度的程序呢?3 h9 R6 U' v7 n/ A$ M2 h; J+ j
(查表吗?那样表格会很庞大吧?而且取值也不好计算吧?)
1 x8 |% s+ e" X: @2 Y8 y4 J) U. a7 l4 |) P: l, x1 F9 N; C. u* z! a* V
付热敏电阻部分对应阻值表:9 _3 n) ], S3 J6 L
LT804;BValue25/50=4020;R25=100K
# e0 l( f" u7 g8 O" j* Z' p温度 电阻值8 B# R' ]0 d- _3 r" U" t, `
-50 7291.38
8 I. u" f0 U& h5 b8 S-49 6774.88
5 K4 j) {9 T( z-48 6298.61
4 i `2 [) F; l' G2 e) ?: x-47 5859.17
) p( ?" \- `% t-46 5453.45% t7 I4 ^' g: N b- R- K! X+ ?
-45 5078.664 \' Z- Z; q! K' }
-44 4732.22
2 l6 P1 `! u9 Q-43 4411.8 p! V: S9 y6 | Z3 e: R+ m+ }& d
-42 4115.285 I/ V5 F3 P9 s r# [
-41 3840.725 t& E3 ^0 u# ^) ]1 w" h- @7 m
-40 3586.35% S0 c, T; T7 v( }' g! ?
-39 3350.55: F2 }7 [- n9 c& {' c p3 a
-38 3131.85+ q( l4 k( [# q5 U/ ?/ E% P
-37 2928.95 `9 J: M- z( ]) |
-36 2740.46' Y% c+ ^5 f, G1 p" v W
-35 2565.4" w5 _, V: M) X9 S+ ?
-34 2402.69
' s0 d: P' ^7 U0 H+ v0 ^1 ]-33 2251.37: z; |& b: z/ v+ D1 Z% h
-32 2110.58* Q) N4 H2 q$ d9 j
-31 1979.52
9 N* D9 b9 d9 P( X/ `1 Z( Y-30 1857.46
. Y) l0 S2 B* n/ Y* `/ ]8 x- ~3 ?-29 1743.72
4 S# m/ |+ w8 R) E-28 1637.68! B; k( g) ~# f. E
-27 1538.77
- i9 z1 s- O% e-26 1446.47
7 `0 R* {8 X0 Z P8 g2 B-25 1360.3
# K+ c: K1 w+ F8 X' ?-24 1279.82
5 \, w) ]6 Y& o, Y-23 1204.61' o7 L# D% q/ z- {; i, l$ j
-22 1134.29
0 E* v/ {: W' y& N3 g-21 1068.522 t0 o0 i+ v0 D4 Q- v: H. Y
-20 1006.98
8 g- e. _! u d2 e-19 949.368
: o' T, J* U" C% l% j+ I-18 895.411
7 M* t9 z( r& `-17 844.856* r3 h; `6 `0 e0 Q& c" W0 H) d+ p
-16 797.467- S$ R% a5 p& L4 w' e0 F+ u
-15 753.028/ }$ {9 g' [1 H' _# o
-14 711.3384 w! t. l( o" B
-13 672.211( n$ r$ b6 R5 I! j6 N/ E* s0 N2 o
-12 635.474
5 Y$ z( _5 b$ H% k" l-11 600.967
/ a$ |% w0 N) u9 O-10 568.543
' c/ L5 d% w6 K! P7 ?& b" b' l-9 538.0637 g o/ `# K/ k, D- U8 S
-8 509.4# x( ~9 y( m, v2 | J1 y4 \ }7 R H
-7 482.435) j2 z( k1 O+ Q6 b, f5 a6 R- U
-6 457.0578 R- ?8 h5 D. E; @8 c. u
-5 433.165: y2 ?8 c+ q) v6 b0 |
-4 410.663
4 x+ }9 h/ u1 o; {-3 389.462
7 u8 N6 V' T$ d( }9 a! J-2 369.479! `( W+ C1 b" ~) r3 ^& A8 g
-1 350.639
* Z- y( [% \/ [4 c* L+ m! c0 332.868) s& r2 d6 U2 T4 x1 e9 c
1 316.102$ G7 o7 t3 p5 K; I; l; N6 A- ~
2 300.276
5 t4 G- E" G2 a0 z- @3 285.334: {- e5 e& H6 Y6 F% q+ u7 N
4 271.2219 H3 K0 C; I+ R: f* s
5 257.886. P& E* A- r C
6 245.283
) x( b) p2 C- r7 m6 x8 Z7 233.367
: m- Q# C, _% {8 _9 H8 c( I8 222.098, o- E# E/ X5 S
9 211.435
2 ` l2 j0 |# j. l9 v% j( S10 201.345
9 q" ~3 \2 t; Z11 191.792! P4 b7 e8 L. O3 g- `
12 182.746' u0 U# v. E2 F/ @/ W
13 174.176$ |% `+ E8 G0 Q2 O9 a% Z
14 166.056/ r) f: \4 k9 I4 s- z* {+ w
15 158.3597 z2 l) A( S+ m
16 151.06) _1 y& w; x ^/ [9 E8 ^
17 144.138
8 t7 E. t+ R$ c2 Z: E) g18 137.571
& ?9 V/ x0 e; u- Y& ]( S19 131.339
2 o6 L+ ^5 O) d20 125.4233 s+ f/ V# {4 x$ b! M
21 119.805
8 r8 L8 M9 L2 E3 q% e22 114.469" W+ t) o7 l$ A, i* I
23 109.399# {- f; v8 e( q" b l
24 104.581
+ A( p4 F5 _+ o2 M25 100* O( d ?5 _% Y% [( l
26 95.6443
/ r! Z7 O$ _, u0 J/ @, }4 }27 91.50130 j( w' k6 P) v
28 87.5596
# {! a% f- Y( o( Q$ }29 83.8083
9 r, x- g. w. O# B. d. S30 80.23722 r7 W1 h9 D% q+ j
31 76.837
& {2 ~. }) t$ G8 |8 ^# s, O32 73.5984! L) ^# j0 u" ] b( g
33 70.5131 F, \+ y8 w) E1 `" a4 `4 i. } p
34 67.573
9 v, K2 f% {4 p+ d( K1 a35 64.7706* N" `+ `: u5 e9 L# K# z
36 62.0987$ X: H1 P$ E, G, [" ]
37 59.55079 P. M/ q( y9 K' n, p+ G7 Y' X
38 57.1202
# l$ r9 n, ^% Y7 E* A' O# w39 54.8011( A% S' \$ d/ f* P0 K7 C+ u% e
40 52.588
% X3 [4 B: w$ W3 i( C41 50.4753
: E$ W+ i |6 D1 Q% m Q d% m42 48.4581
" `1 u% [% a0 K43 46.5316& u/ u- b4 k- K* R) c X; d) Y+ R
44 44.69135 i$ _( w: k+ z; Y: O; F; t
45 42.933
7 q, {$ N6 Q; s4 m$ C% r: |( p46 41.2525# w; f- A+ x- @4 P6 z3 Q( Q; W
47 47.3965
; J6 { I) A& T48 38.11. e0 G* E& _+ o8 `9 M
49 36.6411
, p! H% P' ?% h- @7 B7 Q50 35.236
`: j8 [7 g# c51 33.8916+ A% o. J& U% E! U9 F
52 32.6050 }6 j1 x) [' K% b3 v* t+ t, T
53 31.3734
9 h- I- J) L; K6 r$ ]5 w/ c54 30.1944
8 g1 @9 V+ M# r+ a/ c+ W' a55 29.06531 V1 U9 ]4 r9 O
56 27.98399 `, E7 n4 m4 w3 p+ E1 T0 r
57 26.94783 q, p. I# j1 W
58 25.95517 `- ~# J) @; q1 n+ ~
59 25.0036 ]9 P3 _; ?/ [+ f
60 24.0915& k; j! _; s7 g5 K2 W1 Y8 J+ I
61 23.217" A6 V" c3 x8 E3 {: V
62 22.3784
, x/ {3 k: L; v4 d63 21.5741 N/ Y. Y" c [; P- H
64 20.8022& t* J0 y- o I: Q5 }
65 20.0617# X7 J* ?' j( f/ E) l5 G. W: K+ A) S
66 19.351
" U. f0 _% c8 B( I! d, W1 T& q67 18.6687- d. x" I& Y# E5 |6 r: m1 M
68 18.01370 G3 E* P D; s+ |4 Y' h2 f
69 17.3847
3 D( G L: p t+ |) y70 16.7805
* ?& s2 x& Y( h! I: _# q1 P# c; A8 W71 16.20014 o! `) \, @5 Q1 _ W8 d* L
72 15.6424' v! V3 }. k! j/ c2 k0 B3 ]
73 15.10646 {4 r+ r) G( v# Y
74 14.5913
. _9 r0 E, i; D2 n) G3 ?: I+ ~) _: T75 14.096( ]; Z2 S) z! V/ O* d' {
76 13.6198: g$ i5 c5 {- W1 s: H! B9 s
77 13.1618; y$ p, Y( u" I; C0 t
78 12.7213' }4 a2 d# A2 @1 J3 J3 G2 ]7 y+ W3 I% R
79 12.2975
6 Z: c* V) P( P" L0 ?9 m80 11.8897: S ^- x) z. l9 a; g$ g/ e0 M' `& N
81 11.4972& ^3 y( r3 g- t3 o4 U7 b
82 11.1195% J7 S% [2 b0 `8 I: p3 w
83 10.7558
! f# g) \3 [ F' r6 ~7 [1 @# F84 10.4056, G, J7 r6 i/ _5 |
85 10.0684
; R: g8 r8 K! X/ P2 H# R86 9.74359 S5 X! p7 O2 {9 R0 ]& w
87 9.4306
1 H) o5 {2 m. b" g* S) |9 `) Y88 9.1291
+ ?$ X/ X8 C% [* A5 Z89 8.8385
1 |% r6 S* N; E( z! \90 8.5585& D: w& o. S/ [* h
91 8.2885
+ T5 _$ d+ d2 I# `! o92 8.0283
0 A( g9 b( ^) }# D' e& D" M7 b93 7.7773
2 L9 ?, a Y% ], Y9 B* g94 7.5352& F! v1 }! T" _# b0 @. p
95 7.30178 J0 i- j5 _5 h9 ?) K
96 7.0764! L1 _2 `4 w: _. w
97 6.8591' d" h/ o& U0 s. G% K
98 6.6493
( ~4 v, K- \0 y2 a+ E% g4 L99 6.4469( G7 ?- }7 I; B5 }( A
100 6.2515
* C' j: Z, u4 |2 p# z/ x" z9 h101 6.0628
9 j( s8 y) @8 ]; \" x( \102 5.8806% V2 t" a; U! b, G" n9 R& ~
103 5.7046
) d. g1 L; t( b104 5.5347# e7 H V. L4 B$ E1 P% @: z
105 5.3705+ E; b" z" D+ i/ x4 U0 C
106 5.2119
4 @6 p4 F( c' Q! g+ W: G107 5.0586
" B* R4 l& U4 y2 `108 4.9104$ c) A, R, ^8 P! j$ z2 d
109 4.76729 `3 y3 O. W" K' A0 l7 ^8 ^! b
110 4.6288
& t$ J, \9 T0 `; V111 4.4957 @- H3 Z- _1 ]' S# \" k4 U
112 4.3655
9 P1 R: p- y( D113 4.2404
! n. O8 x- Z! @ `: q7 q L, G114 4.1193
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