|
|
EDA365欢迎您登录！
您需要 登录 才可以下载或查看，没有帐号？注册
x
本帖最后由 Heaven_1 于 2022-3-10 13:54 编辑
9 s" s9 M9 ?! N$ s! G
+ C0 R. M u, i" F//该模拟串口为半双工模式， 2400/8/N/1* @( k6 M/ I' w- G4 a: @
//如需不同波特率改变T2定时器的时间便可! f4 a- @' P3 i: l! s
) M; `3 r) {. Y8 i+ K+ G; m7 N
. W0 R1 l, y0 N4 ^8 ?: h- P5 ?8 F X7 T
#pragma vector = TIMER2_OVF_vect% W' n8 h, G, i" f" ~, u
__interrupt5 |0 @: R% ~2 ^9 l1 G# v- V
void T2time139us(void)
& r/ j. U' v" b$ i4 b$ ]{
6 E- S' O+ z# T2 h8 ` static unsigned char bit;
! K+ Z1 B9 d3 z ]- o6 s static unsigned char count;
+ [% u! w; m' t$ T static unsigned char stat_flag;
s8 H9 {& P8 R5 E! U. b0 B static unsigned char tmp;( M S4 ]1 ] l, V
static unsigned char recv_byte;& Q0 W R9 U/ k0 v
TCNT2 = 152;
! ]# H6 S2 p0 e( l7 k' y( o ; N. y8 D2 n( N
if((Uart1_RX_overtimer != 0) && (Uart1_RX_overtimer != 0xff)){% i# M9 G% H8 j: w
Uart1_RX_overtimer--;" c% ~' n) ^, P' p& A0 t8 I
}
7 a+ N1 _0 p2 i: X! M2 U/ u
7 Q0 G' e: H* F if( Uart1_RX_overtimer == 0 ){) X6 g. @; X9 W, u1 e8 I
asm("sei");0 c- i, i! w. u
return;) v$ c9 d# ? C' U X
}
+ ?2 n% g( r, |6 t1 g; ] * E1 M) o4 _9 P8 l
if(Uart1_send_haveframe == NONE)5 k1 G2 u" C0 [) q; p
{% ?) T! |6 [" a- ?" K+ B7 Z/ o/ h0 r
if(Uart1_recv_haveframe != NONE) {6 r: l9 P- u8 I: w
asm("sei");
) _3 c) [1 t8 _# u: n return;
' w! n8 S4 g% X }
" ?" Y. f5 Q# u' U8 V& M0 G/ t; v: u: O3 N0 v) Q, Q
if(stat_flag == 0xa5){* ~ ^7 }1 {0 J! s6 {
stat_flag = 0;9 v9 M8 l( ]% m7 c( w
bit = 1;
4 x* T5 I4 a" N$ Z! R2 C1 ^ count = 0;6 }& c s3 e" Y7 j2 ?* M) q
tmp = 0;3 g- Z5 `+ X8 n8 z( k
recv_byte = 0;/ r( P, Y0 M% z: ]4 N1 o& `0 l
asm("sei");0 ?4 B6 J" O }/ H W% C
return;; S" `9 d6 R: f2 @$ s# x
}7 K/ X/ N; U6 F) [
if(bit == 0)
4 h+ t8 ?: i1 f' W+ H9 Z1 P+ G- o' H7 J {
3 Z+ f5 Z* E b if(!(IORxd_PIN & (1<<IORxd_BIT))){
( C' p$ m0 M$ ]6 Z k" W$ Z% e$ X count ++;
2 ` p, x+ f8 H' D- J if(count >= 2) stat_flag = 0xa5;
) _0 ~& {( z3 V p3 ^ }) A, S% T1 O" y
else{
$ z9 c6 A9 r" D `0 i0 X, p6 [ count = 0;3 C9 F& ~8 p i6 Y. N
stat_flag = 0;' k$ |: [7 _, O$ G5 g
}
% w' l- p. V3 ` asm("sei");% K7 p1 [& K8 t% |4 E
return;" P" N5 V0 j3 _3 ]- J0 e4 H5 X0 |$ z
}$ G' \% U. B: z$ X, ~) C: L$ U, z
if(bit == 9)& _% O9 o2 A: V! s
{
0 _/ d N6 E; \' n9 @$ [2 _ if(!(IORxd_PIN & (1<<IORxd_BIT))) {! P% l U/ Y+ A7 |
asm("sei");# C' f; \ m( W! M# S$ D
return;
4 X; S1 _" @. p/ T- R }2 H; {% q5 o e' x* G
count++;
$ H) g6 j* i- K' E if(count >= 3 ){
3 r7 c' f& c, F' H4 `7 B: a bit = 0;. Q/ p F% T. c4 j4 Y: P7 T- I; t
count = 0;4 p! @& C" \4 P8 ~8 [& A" s5 P
Uart1_recv_buf[Uart1_recv_pt++] = recv_byte;
5 |1 F7 C: F! b% _( ^4 X if(Uart1_recv_pt>=63) Uart1_recv_pt = 62;
$ r0 g) J! L; ] Uart1_RX_overtimer = 100;
* J" H. Y8 D$ a }
: k3 r: X4 z$ \. e0 r asm("sei");
; H( l# l" B+ F" F5 t" A return;& A/ ]6 K# Q) U3 M* N4 I
}7 I% L% L- @. F* J" ^
tmp = tmp << 1;. H, Z1 D, k* U, `; K
if((IORxd_PIN & (1<<IORxd_BIT))) tmp++;+ x+ O& Z& a* `5 ?5 m
count ++;
- a+ R# s% I7 |- l# I/ r if(count >= 3){4 G& M/ p( d9 ?% R+ O: o- f+ |* Q
recv_byte = recv_byte >> 1;
) S, V9 e# ^3 J# b9 q9 z2 g4 P/ R if( (tmp==3) || (tmp>4) ) recv_byte |= 0x80;4 A% ^, H- ~; R
tmp = 0;
- ]3 }8 j4 u$ a1 s count = 0;
* X! y" F. U" z0 o bit ++;+ ]* h: A" \) ^. ]8 o
}
; h( A) T. d- ]0 A" ~ }" @1 C4 ?% Q1 I! Z( g( }* x0 R$ D
else
+ M! @' d1 m8 p5 w; E; B {
4 E# U" H8 K" I! g( c( j: X# W7 | count++;
% u( b1 I* e# g* ] if(count >= 3)
" b% s$ A4 J. s- f1 Q {% W$ t+ g. O# N. g5 X1 t
count = 0;
3 b z/ v; n% N if(bit == 0){
& y2 [! \6 G3 |2 w( P& t( k IoTxd_PORT &= ~(1<<IOTxd_BIT);
1 P; m3 B1 e2 ~5 |9 ? }
$ K3 A1 e4 _# v$ L else if(bit == 9), h/ ^2 u3 r, L2 \
{
; S; p/ _2 H. k# ]0 I IOTxd_PORT |= (1<<IOTxd_BIT);
6 z/ [4 ]4 R9 m, h5 Z; @ Uart1_send_pt ++;
) b5 U8 G5 z" G6 Z. w( |. U/ n; I if(Uart1_send_pt >= Uart1_neet_send){
0 N6 q$ P* ?, a o Uart1_send_haveframe = NONE;( [+ U2 I' m7 ?- N3 v9 K' q% v3 @
}
, ?5 M% Z6 m+ M% J; K3 k }, u8 a* U1 L. y( L
else/ `& j) Y2 o7 |& \+ l$ |' P9 I: ~6 \
{6 R0 V. I/ B" m1 Q9 M/ x
if((Uart1_send_buf[Uart1_send_pt] & (1<<(bit-1))) == 0) IOTxd_PORT &= ~(1<<IOTxd_BIT);
: y( A9 ^; w' n0 q3 }8 N! ` else IOTxd_PORT |= (1<<IOTxd_BIT);
- a+ r6 Z1 T* v1 Z }& S& w1 b: O0 _9 h& C4 c4 q8 z5 J
if(bit >= 9) bit = 0;' _! d/ O) f" G( N9 f* V
else bit ++;6 n8 d: e/ p( o' b5 N
}
/ Z( t1 b6 F/ a }0 ~& X" s. c2 t8 G2 D7 C
asm("sei"); : p/ T7 Y+ ^1 `) s3 o
}) C$ P: b, q; H
7 K% F& x: W4 i$ M+ J* f
, {4 k3 c" I- a0 B4 h8 ? |
|
/1 
发表于 2022-3-10 10:14
收藏
淘帖
支持！
反对！