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我用一个调用函数来计算一个区间上的函数值并画图。此调用函数的输出是x = [x1; x2; x3];我想要把三个值的图像都画出来,编写的plot语句却都错了。错误信息:; n l/ h" l( q' H$ T
错误使用 plot。, w6 H+ j1 Q/ |' n, _
数据必须为可转换为双精度值的数值、日期时间、持续时间或数组。
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出错 Untitled3 (line 3)3 Q4 V) `+ I' V* Y2 z# W
plot(y,c(:,1));
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( h0 g/ a9 V: g! }! r. H( M以下是程序,使用的64位R2018。
- s6 h! E* i: W- B! {4 xy=9.9:0.01:10.1;1 W% C: `- V) e# `* [
c=Solve3Polynomial(1,2.*k-20,power(k-10,2)+0.00005,-0.000001);: M% Y( d9 ~: ~) E
plot(y,c(:,1));
5 |' J' u# ?1 C" U; E" v. iplot(y,c(:,2));. b% h6 F" B( A- J
plot(y,c(:,3));3 k4 ?) L& u1 }% Z
function x = Solve3Polynomial(a,b,c,d)
" E: t. d/ y0 \: Z% 范盛金. 一元三次方程的新求根公式与新判别法[J]. 海南师范学院学报,1989,2(2):91-98.
. x8 w1 H1 t* ssyms x1 x2 x3;
3 { J& V h# s# V- l6 h) v* oA = b.*b - 3.*a.*c; if abs(A) < 1e-14; A = 0; end
/ M+ k' e( }3 \1 W. ^7 w+ CB = b.*c - 9.*a.*d; if abs(B) < 1e-14; B = 0; end% X, r: N; m4 ~. s" E
C = c.*c - 3.*b.*d; if abs(C) < 1e-14; C = 0; end
7 D" ?' j" g4 o4 `( W, g* BDET = B.*B - 4.*A.*C; if abs(DET) < 1e-14; DET = 0; end
8 E' L6 f) }7 C3 Wif (A==0)&(B==0)
! y1 V& D5 @7 U& z+ [ x1 = -c./b; x2 = x1 ; x3 = x1;2 \! H; ^+ M# v. b" Q$ z1 J" {
end
' X( f7 ^; Z1 [: \1 \( }if DET > 0
* s, h+ N/ u G- D% b4 w; { Y1 = A.*b + 1.5.*a.*(-B + sqrt(DET));
0 @8 c; v( |) u+ d3 S N Y2 = A.*b + 1.5.*a.*(-B - sqrt(DET));" O3 I2 k% v) l
y1 = nthroot(Y1,3); y2 = nthroot(Y2,3);& A+ Y$ C( g5 f6 v1 q |
x1 = (-b-y1-y2)./(3.*a);) \1 f4 I: V2 g& m" N
vec1 = (-b + 0.5.*(y1 + y2))./(3.*a);
4 n/ A" ?" O w! e4 b vec2 = 0.5.*sqrt(3).*(y1 - y2)./(3.*a);
% s. z; `; e# Q1 S x2 = 0;
3 V+ A( a! w% F* z x3 = 0;2 P% ^# L' t6 o: f& u8 r8 L5 Q" R
clear Y1 Y2 y1 y2 vec1 vec2;
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if DET == 0 & (A ~= 0) & (B ~= 0)
$ y; R( A7 e3 d5 \ K = (b.*c-9.*a.*d)./(b.*b - 3.*a.*c); K = round(K,14);0 L, j8 P( Q) {- E+ R
x1 = -b./a + K; x2 = -0.5.*K; x3 = x2;
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if DET < 0! J- D( K+ _" K: L9 P
sqA = sqrt(A);
( `7 J6 s- v& r& a T = (A.*b - 1.5.*a.*B)./(A.*sqA);
, m' C9 q3 T& i theta = acos(T);
. Z/ R! ?, p2 ?% d; o2 a csth = cos(theta./3);, Y% D+ Q h9 w- k ]% t3 t8 H
sn3th = sqrt(3).*sin(theta./3);" d2 s* q3 w2 X7 |$ F% s7 s: B
x1 = (-b - 2.*sqA.*csth)./(3.*a);
$ ?9 u/ B" k/ d8 Q) z x2 = (-b + sqA.*(csth + sn3th))./(3.*a);+ ?. V3 p1 S, J1 J5 [
x3 = (-b + sqA.*(csth - sn3th))./(3.*a);
# v& h9 G1 Y) U4 ~9 U: Q clear sqA T theta csth sn3th;
0 k6 d) H; w5 P$ a! D: @( n% Gend
, Q5 K* Z6 S9 X& v, d% D, m6 Vx = [x1; x2; x3];' ? Z# N Z8 z, T* @' i
end1 `6 w! z4 G* F } L
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麻烦大神帮忙指点一下,非常感谢! |
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