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计算二重积分的时候,结果就是一个式子,不是积分值,这是为什么呢?求教+ T; p4 H" z0 C; a9 [
1 W) D' ]( g7 k" `6 U代码如下:! V f/ N4 t& }4 b9 @. U4 Y. i/ v
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clear all
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clc
5 |! T7 a, e! k8 R4 wsyms x y
" ^; G3 n3 r" `; A" [ e0 ]1 Womega=1;
2 Y" [' h! ?3 ?0 P) c$ ~- Emu=0.001;
: I" J |$ B; {) _0 q# K6 h( Walpha=0.13;
- B6 D; Y1 V$ j5 [ ~: N8 Abeta=0.0031;4 _3 c/ F5 |/ f: G$ | b- R/ r
u=0.001;v=-0.02;
2 q9 G1 u2 c; L4 D9 P* P- b+ T, \tau=2.2;tau1=1.5;D=0.11;- e" N6 U- f' E* H
tau01=1.42;tau02=1.5;tau03=1.56;tau04=1.9;
$ e- J# n- i! g) d6 o- e' L' Uomega2=1-u*cos(omega*tau)-v*omega*sin(omega*tau01);8 T0 M: u# I/ l7 @
eta=1+(1/mu)*(-(u/omega)*sin(omega*tau)+v*cos(omega*tau01));
8 S* G; n) m; i* PK=D/(omega2.*(1+omega2.*(tau1.^2))); @8 z q. t1 B- g1 r
f1=(1./(omega2.*K)).*exp(-(mu./(1536.*K)).*(15.*beta.*(x.^2+y.^2./omega2).^4-32.*alpha.*(x.^2+y.^2./omega2).^3+96.*(x.^2+y.^2./omega2).^2-768.*eta.*(x.^2+y.^2./omega2)));8 _, o; y3 e4 h! z% S. ^
F1=int(int(f1,x,0,10),y,-10,10)$ i5 i$ ?" t* V6 J2 K
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K1 O- d$ {$ n$ U2 M/ L结果:
+ `$ b* E* s- ]; p, w% l7 CF1=2 V% p% ~5 S+ B) E3 M5 _
int(int((1029484437153*exp((76368780973521777*(x^2 + (2251799813685248*y^2)/2297649917499219)^3)/922337203685477580800 - (17623564840043487*(x^2 + (2251799813685248*y^2)/2297649917499219)^2)/9223372036854775808 - (546330510041348097*(x^2 + (2251799813685248*y^2)/2297649917499219)^4)/590295810358705651712000 - (3488543873076974433998624506509*x^2)/81129638414606681695789005144064 - (1162847957692324811332874835503*y^2)/27593854166072889506733609713664))/34359738368, x, 0, 10), y, -10, 10)! @" ?$ j6 U0 g E2 R
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