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6 }! _" g; A$ Y* R) T% i单位样本序列
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+ _" C* `5 j: H% P# l+ @5 l- T- clc
- clear
- close all
- n1 = 0;
- n2 = 5;
- n0 = 3;
- n = [n1:n2];
- x = [(n - n0) == 0];
- stem(n,x,'filled');
- ylim([-1,2]);. G) R: \. L7 B5 H4 d$ ]" y0 b; I
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' `7 r9 E0 s5 ^改成一个函数：0 @0 p+ I1 i. k- x2 Z
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- function [x,n]=delta(n0,n1,n2);
- % generate x(n) = delta(n - n0); n1 <= n <= n2
- %_____________________________________________
- %[x,n] = delta(n0, n1, n2);
- %
- n = [n1:n2];
- x = [(n-n0) == 0];3 }6 E5 t; ^/ t- N6 r7 L0 `7 k
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命名为delta.m
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新建一个脚本：
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- n0 = 3;
- n1 = -3;
- n2 = 6;
- [x,n] = delta(n0,n1,n2);
- stem(n,x,'filled');
- ylim([-1,2]);
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6 E7 F; l% }6 ?( u+ a运行得到：. m2 [6 [& t+ j! t
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单位阶跃序列
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0 k8 y8 Y* S2 H6 D0 T; x n4 y w直接写成函数形式吧：
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- function [x,n]=stepseq(n0,n1,n2);
- % generate x(n) = u(n - n0); n1 <= n <= n2
- %_____________________________________________
- %[x,n] = stepseq(n0, n1, n2);
- %
- n = [n1:n2];
- x = [(n-n0) >= 0];
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新建一个脚本，测试：
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- clc
- clear
- close all
- n0 = 3;
- n1 = -3;
- n2 = 6;
- [x,n] = stepseq(n0,n1,n2);
- stem(n,x,'filled');
- ylim([-1,2]);* t5 F% d8 d% E1 n! e
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结果：
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实值指数序列: L! G% j0 {$ }7 u0 ^& E
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为一般形式。2 E: U7 z6 G0 j$ V
- ]# V: d W4 H e, N下面产生一个序列：6 ]# h* z/ c* s! a+ e- M. Q
+ ~2 {" w+ t) r, `; }$ h! F
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脚本代码：
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7 U) K7 M8 W1 @6 R% s. W) D9 @- clc
- clear
- close all
- n = -3:10;
- x = 0.9.^n;
- stem(n,x,'filled');
- xlabel('n');
- ylabel('0.9^n');
- xlim([-5,13]);
- ylim([0,2]);& z! v8 l* R: P# C2 a
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复指数序列
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2 b& j. m( I4 O- clc
- clear
- close all
- n = 0:10;
- x = exp( (2+3j)*n );
- stem(n,x);
- xlabel('n');
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# S& b- D |1 {* b( A- \0 m周期序列* f3 Y5 K+ O# E9 T# G6 u* W
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- clc
- clear
- close all
- n = 0:10;
- x = exp( (2+3j)*n );
- subplot(2,1,1)
- stem(n,x);
- xlabel('n');
- title('Not Period Sequence');
- % the number of period
- P = 5;
- xtilde = x' * ones(1,P);
- xtilde = xtilde(：）';
- subplot(2,1,2);
- stem(xtilde);
- title('Period Sequence');
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发表于 2020-1-2 10:49
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淘帖
支持！
反对！