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这个是我的循迹小车程序,我的问题是小车速度太快了,但是速度降不下去,似乎是PWM用错了。
6 q) r: D1 }; ]本人新手。% T6 |7 u% w3 k- m
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#include<reg51.h>; J% V/ L& ]. F
#define uchar unsigned char
2 j" f" @& Y& c1 F( v9 o5 k- a#define uint unsigned int
( C9 l+ V/ Q1 {$ I7 Y$ a sbit PWM1=P2^5;
: b0 I4 A6 T8 H' O5 ^ sbit PWM2=P0^7;1 P4 V9 X+ [3 }5 c" j( N
sbit PWM3=P2^4;3 L# B2 z( i9 p8 b- y7 `# S
sbit PWM4=P0^4;
7 S1 I/ y% a9 X* A sbit IN1=P2^2;//左1前
+ U$ S! [; w2 F1 ? sbit IN2=P2^3;//左1后 j3 F5 i N! d y% M0 ^8 C" [# ]
sbit IN4=P3^2;//右1后
" h. P& [1 x1 {1 e1 ^" @3 i8 | sbit IN3=P3^3;// 右1前# k4 z5 E- ?/ C
sbit IN5=P2^0;//左2前 0.: g0 U. P$ d+ e/ Q; p' C
sbit IN6=P2^1;// 左2后" H" b2 q; Q: p* F% [
sbit IN7=P0^1;//右2前
5 p0 Y- S% N. S& Q& y sbit IN8=P0^0;//右2后9 x0 Y& z' G: w- {- w6 r
sbit Z1=P1^7;//左边第一个传感器9 w4 O& G; B2 |2 I% t+ a, k5 \% j
sbit Y1=P1^3;//右边第一个传感器- G! v3 o( ^: E+ G
sbit Z2=P1^6;//左边第二个传感器
& i; k" F0 u# o8 N5 C6 Y' W sbit Y2=P1^4;//右二
5 W7 j- X, P5 _ sbit Z3=P1^5;//中三( k3 N1 o- A; Y9 L( r4 j0 ~
sbit c1=P1^0;//侧灯c1
0 U/ H4 @# i: ?& U3 w/ u+ ^/ ] char count1=0;//计数器1
0 T q- x* R% G% B char count2=0;
$ i3 e' \+ w' O& ?, ^/ q char count3=0;//计数器1; q2 t% W. p8 x( l/ J
char count4=0;
* o0 f7 Q( k0 u$ y, R, d9 g/ W int y=0;
+ N& c) N: y0 X0 n. c char sd1=0;+ ~; f5 R3 q5 [! _, d
char sd2=0;
9 @( C. A8 ~, ~" s$ B% Y char sd3=0;
" }$ C/ [& r7 e5 K5 ` char sd4=0;
: E9 I/ O( u/ {0 a4 d //void delay(char z)
' K1 u: t6 R: ~) ]+ j; I // { 0 @ i, i0 ?% @* F9 A* b
// for(z;z>0;z--)
" X( X- B5 X3 e! ? //for(y=0;y<110;y++);
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//}
. m# Y ?/ ?" Y0 W" E1 k void forward_turn1() //左1电机前进" d& z- r* ^4 i- @
{
9 L3 [ f. u9 I* f+ i2 f1 {2 F F; r IN1=1;
* ?6 s1 F: j7 ~6 Z$ i5 `7 k8 A" t6 j IN2=0;+ }& u2 p. _0 h2 o+ s- M
sd1=40;
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& q# K0 ], r& \1 w4 {+ c void stop_turn1()//左1边电机停止
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IN1=0;. n" ?; d [' {3 W
IN2=0;8 P( M/ o: ?8 u" O& |% o% W
}
7 G6 _) m# {' v; _" Y" n7 l6 f5 f void forward_turn2()//右1电机前 进
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IN3=0;9 S9 r4 n% ?4 w- u' t! e' @. u
IN4=1;
* j' ^, K( r; E" v% X' M8 F sd2=40;6 y- f4 J5 L1 A) L, v% e: U# \
}
8 P6 n8 o6 _% j& q/ X/ T void stop_turn2()//右1电机后退+ P, m; Q* B) Q9 |% G9 |0 r
{
5 B: p( |: |6 m" T3 L" r+ K IN3=0;
; b* U* b4 x, X& w IN4=0;1 i) a& a& I( j F! A) e
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void speed1(int count1,int sd1)//左1控; y, ]& j6 K1 N4 _+ ]/ e
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if(count1<=sd1)
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PWM1=1;
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else
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PWM1=0;
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}
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//右1边电机速度控制7 g7 H6 Y$ ]/ A) R
void speed2(int count2,int sd2)3 \7 Z# t0 [, h9 p8 W& g
{
. m1 {8 _# s0 q* v& o7 K# J+ f& w if (count2<=sd2)
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PWM2=1;
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}
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PWM2=0;' G3 Z3 y2 S( H5 H
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}
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}
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void forward_turn3() //左2电机前进# E- d8 Y8 D2 K! m: m5 E
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IN5=1;
2 N! Q% \ b( P b8 K) m IN6=0;6 J4 ~5 z4 o/ ]+ g: |, q
sd3=40;/ ]+ o; d- R5 V O# ]
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void stop_turn3()//左2边电机后退
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IN5=0;
' ]# o) Z9 W8 g! J' z8 G0 ] IN6=0;& n& g4 m5 C, I1 Z: i8 y& n8 \
}
0 S% X2 L6 u Q. D' q! Z( Z void forward_turn4()//右2电机前进
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: n+ K6 F% @9 K2 E: U1 }! I IN7=0;
: i* ^& ]. G& L) O) V. V' x+ U IN8=1;
# P4 a# I4 i# I( _9 B6 c4 x, U sd4=40;
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. k2 d# H5 j; Q void stop_turn4()//右2电机后退
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: A, H+ |3 `* K- y IN7=0;0 s) Q9 L% g- Y+ P' G" N/ e
IN8=0;
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5 r) g, Y3 d8 E7 E# K6 P void speed3(int count3,int sd3)//左2控
& b3 h9 f* K6 U1 k3 W* @4 S4 B) f6 ` {
/ b$ v# p+ N2 h; r$ s if(count3<=sd3)
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* \8 y" W0 X4 x3 X# ] PWM3=1;3 ~8 [% c$ K; q7 F+ Y
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else
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PWM3=0;
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9 {0 ]7 @$ ~, i+ N5 u9 b //右2边电机速度控制$ F4 K, K! r3 ~% h7 |* H
void speed4(int count4,int sd4)- d! m$ `5 B$ K$ u
{
+ K- _& p, G2 x+ Q if (count4<=sd4)
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9 X( `4 y J! `8 O2 H PWM4=1;
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}
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( _, H0 r. }$ I9 S) Y! L PWM4=0;7 V% Z8 K0 U7 K: c: h
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}
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void advance (int ct1,int sd1,int ct2,int sd2,int ct3,int sd3,int ct4,int sd4)
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forward_turn1();
. a! [5 j# {/ ~: L forward_turn2();7 ]3 W# N/ }6 E- N/ M
forward_turn3();
% l0 _( z5 q. T: k% ~* T2 K$ H forward_turn4();+ _" \+ J3 Z v3 B; B
: o: T0 D5 J2 d$ J. P, e& ^' C speed1(ct1,sd1);* V* P" |% s% \: Q& e3 y
speed2(ct2,sd2);3 o2 P4 G0 u3 ?& x; ]( U& f
speed3(ct3,sd3);
$ o: h2 A _3 e# ]' B$ S speed4(ct4,sd4);
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}//直线前进
0 {4 T& C4 m& q# i/ I% W void right_turn(int ct1,int sd1,int ct3,int sd3)//小车右转
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forward_turn1();6 ~' u, @. T( y) @8 m* Y9 Y9 l
forward_turn3();
& W4 `9 A0 \$ X stop_turn2();
$ q' h1 G4 i6 B' x3 D stop_turn4();
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speed1(ct1,sd1);
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speed3(ct3,sd3);
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; a& q( l$ j3 ^) v: r$ P void left_turn(int ct2,int sd2,int ct4,int sd4)//小车左转
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forward_turn2();1 C& k6 X7 y/ g9 O6 P
forward_turn4();! o0 G$ B) L+ w$ A9 T& I B& t
stop_turn1();; y6 u) i! s9 n" A% j4 T+ S* X
stop_turn3();9 a( a$ `! c0 f9 Q1 }( f
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2 F) Z, x6 f; B speed2(ct2,sd2);& L: ]6 P0 _, I' Y1 g2 C& ^
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speed4(ct4,sd4);* h/ x' N A& V) Y/ T6 r6 `/ f
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% r6 k% h" I7 H/ a# ]. N S main()//主函数1 A: T8 p4 B! y
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TMOD=0x11;6 E! g+ y* v" `2 m$ {
TH0=(65536-1000)/256 ;
0 \! n! F) p: a8 t" z4 L+ s/ p TL0=(65536-1000)%256;
, L+ l8 D3 r5 h$ ^7 J EA=1;# \7 o- _' e% c. `
ET0=1;- N2 g7 m F' p4 y
TR0=1;9 b/ ]. r; x7 n/ T% k3 G8 `" D1 Y
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TH1=(65536-1000)/256;0 [9 {- G0 B( p5 }% j+ T& \
TL1=(65536-1000)%256;9 r8 v X' U$ P& ]0 E1 O
EA=1;
* c1 _0 {2 _4 l/ Q9 O ET1=1;4 X7 R7 D$ v/ @$ l6 c/ e
TR1=1;+ Y% F( d6 M' K) Y
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0 u* p; K) b# b while(1)" e4 e0 i: g5 X
{
0 H" w/ W+ |- B! R if(Z1==1&&Z2==1&&Z3==0&&Y1==1&&Y2==1)//中间感应到,两边没感应
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advance(count1,500,count2,500,count3,500,count4,500);
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3 t2 E/ U6 }* G. u8 a( D if(Z1==1&&Z2==0&&Z3==0&&Y1==0&&Y2==1)
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advance(count1,500,count2,500,count3,500,count4,500);//中间三个感应/ E0 R/ K# e3 ]
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if(Z1==0&&Z2==0&&Z3==0&&Y1==0&&Y2==0)
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advance(count1,500,count2,500,count3,500,count4,500);//中间五个感应
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* Z1 i) b* z% P4 `0 e+ ~ C+ i6 J if(Z1==0&&Z2==0&&Z3==0&&Y1==1&&Y2==1)//左侧三个都感应到. x: Z6 f8 e e) X+ V+ U
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left_turn(count1,200,count2,700);9 y% d& s! }# i8 ]7 E6 o& ?7 m e! e J
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if(Z1==0&&Z2==0&&Z3==1&&Y1==1&&Y2==1)//左侧2个都感应到
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4 v% P6 H4 X9 Y; l z" i; N2 J left_turn(count1,200,count2,700);- X3 u! b4 l$ D
}
, V3 e, r/ c/ y. f7 [9 k if(Z1==1&&Z2==0&&Z3==1&&Y1==1&&Y2==1)//左2都感应到4 k" ?% e, `5 h5 B
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left_turn(count1,200,count2,700);
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if(Z1==0&&Z2==1&&Z3==1&&Y1==1&&Y2==1)//左1感应到
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' T1 t+ i! a7 F: f6 ~: Q left_turn(count1,200,count2,700);
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if(Z1==1&&Z2==1&&Z3==0&&Y1==0&&Y2==0)//右侧3个都感应到
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right_turn(count1,700,count2,200);
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if(Z1==1&&Z2==1&&Z3==1&&Y1==0&&Y2==0)//右2都感应到
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right_turn(count1,700,count2,200);6 q, ?- A- D/ q# D* d
}
% d- ?9 J+ C9 f2 v1 R5 T* W if(Z1==1&&Z2==1&&Z3==1&&Y1==0&&Y2==1)//右2感应到3 }! B- N' H* {/ l) H; V
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right_turn(count1,700,count2,200);6 ~' ]) h! N2 s4 f9 k5 }
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if(Z1==1&&Z2==1&&Z3==1&&Y1==1&&Y2==0)//右3感应到
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( t& h; R J7 Z& ~1 B( q' F& O; M right_turn(count1,700,count2,200);
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//中断服务器% |3 |/ f; Z' q) S2 w5 r' v
void Time0() interrupt 1 / D; D# [0 Z1 N. R7 j7 @; H1 Q
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TH0=(65536-1000)/256;1 u7 o2 R# B& u" G
TL0=(65536-1000)%256;
; Y; b* Q" P8 I+ K8 u% c count1++;% z+ J0 S, R: g$ n
if(count1>=1000)
( f+ S( S6 y5 w( A: O) m0 C count1=0 ;3 B- `3 T" k1 L1 a7 D+ F# R! L& B' u
}
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void time1() interrupt 30 ~0 ~$ Y% h1 H. F6 R4 G* V
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TH1=(65536-1000)/256;6 g6 |0 l' P" u8 s
TL1=(65536-1000)%256;0 ^# h: }$ K" b4 S
count2++;' s# G: H4 ]! C0 o6 k1 H. c
if(count2>=1000)( H& Z+ i7 H k0 m. K6 J
count2=0;9 Y; Z; k; E. w( |* ]+ [% c1 E
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