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这个是我的循迹小车程序,我的问题是小车速度太快了,但是速度降不下去,似乎是PWM用错了。
; U( O1 K" \9 D7 W# h) G本人新手。
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#include<reg51.h>
9 F0 B$ ^9 B+ G2 D( _#define uchar unsigned char
' h: ^: u3 ~' O0 Y* k#define uint unsigned int 0 D* I9 x- d8 i6 g$ S5 @% s
sbit PWM1=P2^5;
9 M6 U# _. m% f. |7 g, [, M6 l sbit PWM2=P0^7;
! r5 U. }* ], n7 m4 Y( L8 H O sbit PWM3=P2^4;9 B6 p$ o7 _9 P* ?
sbit PWM4=P0^4;% v1 N% M; m! _' ^7 y/ \
sbit IN1=P2^2;//左1前
! _5 p6 w8 ?( I8 P* x# |1 |$ ]9 z sbit IN2=P2^3;//左1后 ^% {& Q; k) P5 q
sbit IN4=P3^2;//右1后 ' O: k# e5 a" W
sbit IN3=P3^3;// 右1前
& G1 K' R/ r; f" D sbit IN5=P2^0;//左2前 0.
& _. d7 f3 ]- I8 \6 ~9 E+ R7 K sbit IN6=P2^1;// 左2后5 _( W& W" P7 F7 [ [) S
sbit IN7=P0^1;//右2前 5 [1 k+ g' F* h6 o% y+ M
sbit IN8=P0^0;//右2后7 l' K$ h8 n2 F- ]4 s
sbit Z1=P1^7;//左边第一个传感器4 U' t% e. D- H/ V
sbit Y1=P1^3;//右边第一个传感器2 Z% W$ H- h2 ]4 x, }
sbit Z2=P1^6;//左边第二个传感器. P, p% ~; O3 g( k# j1 q
sbit Y2=P1^4;//右二
4 m& D! w; H2 X4 ^3 W sbit Z3=P1^5;//中三/ V: i4 X) ^/ b* U$ P# c
sbit c1=P1^0;//侧灯c1- A c$ [: J9 T. X
char count1=0;//计数器12 u1 u! j: ~4 H9 i
char count2=0;
2 S( y$ l% ^" B$ p4 C char count3=0;//计数器1
, O" w, v7 L; D" p' P char count4=0;
5 `* \! W4 J- O2 f2 c int y=0;
( }. R% O- a' M M7 G; W char sd1=0;
' A6 q' M# D0 x, n! Q" u8 Q i/ E char sd2=0;8 I7 P: q3 q: M# u: i! M" n) A% H% ?
char sd3=0;
# o6 i1 p/ X1 e5 U char sd4=0;% \7 X, b% M: G/ e' g' {" {
//void delay(char z)3 W. C1 u: c% g3 n" i2 U
// {
7 i8 h) U5 r' Q. `# b z+ @ // for(z;z>0;z--)3 I5 m3 p5 ~7 `1 l
//for(y=0;y<110;y++);
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5 c. n3 S- f- G7 J8 l5 `5 g //}! U; x- a+ `+ w) y+ N& U4 L
void forward_turn1() //左1电机前进1 H# f) V. D# N6 c, }, V
{
# w5 ~: H6 U+ e: j9 z& s IN1=1;, k' O1 C: R' a1 ^
IN2=0;1 N. V7 G: X! T& W( U
sd1=40;# e6 D! V0 s8 k4 l# Y/ V; _% v
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void stop_turn1()//左1边电机停止
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1 y& ]2 j) `* M, w% A IN1=0;& k& ?9 \5 u& G/ Z" e
IN2=0;
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% `6 r$ ~* W' |- q. S0 j; ? void forward_turn2()//右1电机前 进
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0 \. h: G& H6 x* r: f9 F0 n IN3=0;
8 P, S/ r5 \* R {# i6 v, G' V IN4=1; 3 N8 y$ I. }' l/ y0 {, l3 F
sd2=40;
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void stop_turn2()//右1电机后退
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IN3=0;+ [. B" G& g, `
IN4=0;
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void speed1(int count1,int sd1)//左1控
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5 s( G- m' w# _8 [- A, L3 R3 s/ B if(count1<=sd1)
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PWM1=1;& G* _8 p& v) u/ n6 i% [( j
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else. b9 A! b" r+ E3 _0 b/ a
{
) F' W4 d8 u; c" c, F PWM1=0;! p, P9 M! x* I: m0 ^, `
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}
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2 _* e- f O* P9 V* _ //右1边电机速度控制7 p$ g" E: [. R- g1 P1 Q
void speed2(int count2,int sd2)
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if (count2<=sd2)& |. O# V0 o# _( l: H; f# Q/ H
{
# y5 o( G) Y$ z' n( ~ PWM2=1;
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1 @6 j5 U2 {; O- K! }5 E else
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9 W5 B9 H9 H6 [8 p3 @ PWM2=0;
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6 k$ u0 a1 O- k8 ?3 A' M void forward_turn3() //左2电机前进. V7 L. U( O) z6 H1 U8 c) Z
{- G: A8 `1 V! p8 a
IN5=1;
/ e& _+ f: h" P$ e7 W1 O IN6=0;
. T! Z V; _5 t* z sd3=40;0 {5 n1 l# U# U% b3 `
}
7 W% @" ]9 a) M8 i, }1 h void stop_turn3()//左2边电机后退
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IN5=0;- j' P/ \4 u! e8 {
IN6=0;
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" C f+ \2 @& I4 E. E void forward_turn4()//右2电机前进
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0 n% x6 O* X b IN7=0;
" p! p" c# Q& f4 \( p% w" E+ _, X IN8=1;
: S" B: c- Y2 @ sd4=40;
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void stop_turn4()//右2电机后退3 s" M: G8 z: P% l4 v( A, ?. [
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IN7=0;( x5 U1 u2 J- e: k
IN8=0;
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: P8 Y1 K2 o5 m+ b' C void speed3(int count3,int sd3)//左2控
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if(count3<=sd3)* x9 Q8 V7 q0 g2 o- Y: B
{
9 T/ W. `6 L, F PWM3=1;" `- `$ ?! K$ E8 T: F! Y& L3 D
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}
, y" G7 ], M S, e- w/ { else
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PWM3=0;
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( x' y j5 @" V- `9 z# b( ?. { //右2边电机速度控制" V- i" ?! Q. ^, F
void speed4(int count4,int sd4)
c+ z& f) O5 y t {
$ i/ Z. X: f1 [. k* h& M if (count4<=sd4)
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2 H \, p9 p) o0 j# T. P PWM4=1;
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else
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# ?; @2 \3 ~. m0 @ PWM4=0;# X* s6 u" o, ^. }/ ^6 w. X5 h
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" C( j h3 `, E' \6 G+ @. T void advance (int ct1,int sd1,int ct2,int sd2,int ct3,int sd3,int ct4,int sd4) 8 Y/ a9 Q' J w! F5 d9 b
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forward_turn1();
2 h; y9 F/ K! {+ A2 Z forward_turn2();
0 U' ]( W9 C |" J1 b, a0 @4 J forward_turn3();+ T G" {' I; O8 j! |
forward_turn4();
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! s: E, D0 y3 ]& ^ speed1(ct1,sd1);
, K) T7 d6 Z" [5 W$ w. R speed2(ct2,sd2);0 Z- }( X% d6 Y% D# O: [
speed3(ct3,sd3);
, @, t4 f8 q1 \ speed4(ct4,sd4);
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; _& q" H4 V) n6 E" W: B }//直线前进) k& o6 O# W% J' P& S
void right_turn(int ct1,int sd1,int ct3,int sd3)//小车右转
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R" `7 b( R8 I- t: I forward_turn1();
3 d' r6 q3 w/ T0 y. W# u$ ? forward_turn3();
1 ]& D" h, R# ]0 j stop_turn2();- b& y8 w( p S0 r/ T& ^9 y5 t( p, S
stop_turn4(); f4 ^2 m+ Z8 S, W- g I( `
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speed1(ct1,sd1);
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speed3(ct3,sd3);
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void left_turn(int ct2,int sd2,int ct4,int sd4)//小车左转2 R/ |4 G! o( n
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forward_turn2();
/ d8 q1 R; f5 n) {8 B4 Y. }2 }; D forward_turn4();/ p4 _+ o. {" ~: \- B* J
stop_turn1();
8 E( \# F" u5 P, S* A \ stop_turn3();7 ]. T# K& e/ \$ r
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speed2(ct2,sd2);
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9 d/ Z4 ?/ R# [3 e3 I& a speed4(ct4,sd4);
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# Z4 z5 q1 Z5 C# g main()//主函数' @6 U P0 i P* ?
{1 o- b& D( i2 ?
TMOD=0x11;
/ U) s( U% l4 R. c0 |+ p& J TH0=(65536-1000)/256 ;5 M" X, S( ?, h9 `# P5 L; \4 c# K
TL0=(65536-1000)%256;
) B$ v: B. Z8 z) z. [/ D a3 ] EA=1;
- O& o& M& E, k5 r ET0=1;
# x* K# e6 h3 @+ T( L- J TR0=1;/ s* ` U9 r) s
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( S. Q4 ?; d* Z, t9 f TH1=(65536-1000)/256;
7 j! C4 B- R5 k TL1=(65536-1000)%256;
8 ?( C3 x7 S, ] EA=1;# ~. s% ?( ~6 V2 E- M! i
ET1=1;! O1 E! l' W4 x7 S
TR1=1;' p- H' D: K# ?, `1 H6 M
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while(1) m" k% `0 D/ Z1 }9 f* X: U
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if(Z1==1&&Z2==1&&Z3==0&&Y1==1&&Y2==1)//中间感应到,两边没感应9 S" K d, E8 a& |% P
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advance(count1,500,count2,500,count3,500,count4,500);
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if(Z1==1&&Z2==0&&Z3==0&&Y1==0&&Y2==1)
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( d1 y3 G9 [/ F. g! ` advance(count1,500,count2,500,count3,500,count4,500);//中间三个感应+ q$ l4 m3 r* _/ @# L, W3 Z/ v
}
N, y/ w0 |$ t O Z if(Z1==0&&Z2==0&&Z3==0&&Y1==0&&Y2==0)+ s* k3 ~# ?* Y
{; r' b* S4 Y+ Y a6 ]; a% t
advance(count1,500,count2,500,count3,500,count4,500);//中间五个感应3 k5 F7 b( r+ n/ ]- ~. @! Y
}
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if(Z1==0&&Z2==0&&Z3==0&&Y1==1&&Y2==1)//左侧三个都感应到4 _* S5 B; u: w' D' W! j
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left_turn(count1,200,count2,700);! T2 W1 i9 F1 [" Q
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if(Z1==0&&Z2==0&&Z3==1&&Y1==1&&Y2==1)//左侧2个都感应到8 l. o6 T0 e. z' M; P
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left_turn(count1,200,count2,700);& h, ^% ~$ l$ l. w5 Y! Q h
}
( M4 A! [6 o4 w3 q* F+ i! s& C8 s- j if(Z1==1&&Z2==0&&Z3==1&&Y1==1&&Y2==1)//左2都感应到2 t/ n1 v# |( N5 n5 r/ `
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left_turn(count1,200,count2,700);
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if(Z1==0&&Z2==1&&Z3==1&&Y1==1&&Y2==1)//左1感应到
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; f) O6 r* j* E# W6 l7 @+ u6 w' x left_turn(count1,200,count2,700);
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if(Z1==1&&Z2==1&&Z3==0&&Y1==0&&Y2==0)//右侧3个都感应到
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" q8 H0 o$ H! N/ T+ O" |4 q right_turn(count1,700,count2,200);6 P9 b$ n# z7 @4 b
}
3 {* L% ]3 }% N8 d$ c9 n if(Z1==1&&Z2==1&&Z3==1&&Y1==0&&Y2==0)//右2都感应到
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right_turn(count1,700,count2,200);8 K5 g+ j8 y& a: { Z; h
}
1 H5 y1 _* y7 ^) d( `; `& Q# ? if(Z1==1&&Z2==1&&Z3==1&&Y1==0&&Y2==1)//右2感应到/ x' `6 F$ d: J; U, x0 s' Y7 c; ^
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right_turn(count1,700,count2,200);4 h T' c: [2 k5 e5 l( I! c; Q
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if(Z1==1&&Z2==1&&Z3==1&&Y1==1&&Y2==0)//右3感应到
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; h7 ?) `4 c$ @ right_turn(count1,700,count2,200);) s7 T, D3 b% Q9 i
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//中断服务器# L( q. ^. J5 N( p3 K# h: k0 I
void Time0() interrupt 1 9 L* |4 f+ ]0 _3 p
{
1 q* D( f* s; q5 B% I5 l3 g9 {9 m TH0=(65536-1000)/256;4 t! R) ]5 D( i/ E
TL0=(65536-1000)%256;! D( N* m+ |% w6 f: ]
count1++;
4 d% Q' \: R1 Y if(count1>=1000)
( `# t% ]4 e. U* v& d- [1 ? count1=0 ;/ {1 b; n# t: c1 l5 [
}
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void time1() interrupt 3
+ {9 B5 ` y! Y4 @ {
' G: k2 d5 ~" J) D1 n- j) g TH1=(65536-1000)/256;
. [! ? ^( T+ G; ^$ U# V TL1=(65536-1000)%256;6 C# @* N2 @: H. u0 u
count2++;, v: H: e7 U" m* E
if(count2>=1000)
) k. p2 ~6 i$ U7 h count2=0;$ `( B$ Y/ ^' J- B
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2 @6 h2 {+ a- _5 v1 j }
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% \$ Z: r7 w, p
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