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这段文字如何理解呢?为何会进入亚稳态?

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    2020-1-14 15:59
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    发表于 2007-12-18 21:19 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式

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    这段文字如何理解呢?为何会进入亚稳态?; D( Y: s& X2 o' C" Q4 t" |8 O! h

    2 F. i8 w6 O$ i* N' FIf the asynchronous reset is released at or near the active clock edge of a flip-flop, the output of the flip-flop could go metastable and thus the reset state of the ASIC could be lost.
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     楼主| 发表于 2007-12-18 21:50 | 只看该作者
    The biggest problem with asynchronous resets is that they are asynchronous, both at the
    0 A* ]8 f* S9 z, H9 \assertion and at the de-assertion of the reset. The assertion is a non issue, the de-assertion is the
    * G% z, S* F4 _: S& qissue. If the asynchronous reset is released at or near the active clock edge of a flip-flop, the
    2 Z5 @* K# E" ~, \! M# Goutput of the flip-flop could go metastable and thus the reset state of the ASIC could be lost.
    ( o8 b, n3 [# ~! CAnother problem that an asynchronous reset can have, depending on its source, is spurious resets
    5 C! Z6 V1 q: _, i8 A; z% adue to noise or glitches on the board or system reset. See section 8.0 for a possible solution to+ L& `  F4 i$ y* }+ u' L1 A0 W+ h
    reset glitches. If this is a real problem in a system, then one might think that using synchronous
    % h9 k1 b% O9 p# f3 L! \7 qresets is the solution. A different but similar problem exists for synchronous resets if these: @% f4 g( W( o6 i2 H2 t. P
    spurious reset pulses occur near a clock edge, the flip-flops can still go metastable (but this is
    % ]8 x0 w. L2 e7 T9 _7 rtrue of any data input that violates setup requirements).
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