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这段文字如何理解呢?为何会进入亚稳态?

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    2020-1-14 15:59
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    发表于 2007-12-18 21:19 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式

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    这段文字如何理解呢?为何会进入亚稳态?/ E& D( X4 [; N' Z
    , c2 G  H4 B9 c2 G2 D  }
    If the asynchronous reset is released at or near the active clock edge of a flip-flop, the output of the flip-flop could go metastable and thus the reset state of the ASIC could be lost.
  • TA的每日心情
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     楼主| 发表于 2007-12-18 21:50 | 只看该作者
    The biggest problem with asynchronous resets is that they are asynchronous, both at the
    ! Q( q3 w3 x3 W& E+ aassertion and at the de-assertion of the reset. The assertion is a non issue, the de-assertion is the- d' K1 [8 a! @' u
    issue. If the asynchronous reset is released at or near the active clock edge of a flip-flop, the6 G) O3 z4 a+ N# ?8 N
    output of the flip-flop could go metastable and thus the reset state of the ASIC could be lost.$ E0 X1 [& ^4 e& q" I
    Another problem that an asynchronous reset can have, depending on its source, is spurious resets
    ! m. t8 e+ h' s4 s) A7 d, i1 jdue to noise or glitches on the board or system reset. See section 8.0 for a possible solution to- a7 E/ R! o2 M1 @
    reset glitches. If this is a real problem in a system, then one might think that using synchronous& ~9 Q7 w" r) K3 w
    resets is the solution. A different but similar problem exists for synchronous resets if these4 J+ z3 M" g1 x
    spurious reset pulses occur near a clock edge, the flip-flops can still go metastable (but this is; X: H& H! c& [: a* y& g
    true of any data input that violates setup requirements).
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