TA的每日心情 | 奋斗 2022-1-21 15:15 |
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签到天数: 1 天 [LV.1]初来乍到
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已知(q_-p_*alpha)^2-(N^2-alpha^2)*p_*(po-p_) = 0, 其中q_ = qc + b * (qq - qc); p_ = pc + b * (pp - pc). 求出b的表达式。6 W @8 h+ |. N+ j, B \9 S0 M
代码如下:
) |; z* A+ R* k" E% Define the given equations {3 o. P! m; d- w* ~. c
syms pc qc N alpha po b pp qq q_ p_
- U! j1 V6 g1 H+ ^5 Ieq1 = (q_-p_*alpha)^2-(N^2-alpha^2)*p_*(po-p_) == 0;- u1 p* B8 \! }
eq2 = q_ == qc + b * (qq - qc);
& l8 O) Z8 S, q, I, O- ]9 weq3 = p_ == pc + b * (pp - pc);
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% Solve for b; T& G' I* H' C! q
eq4 = subs(eq1, [q_, p_], [eq2, eq3]);
\3 p* g( ]" z& N4 W" Ldisp(eq4);7 _& I" F# H3 Y+ `
b = solve(eq4, b);
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: U7 b q# }0 {& a2 X运行会报错,求各位大佬帮我看看是哪里出错了,感谢!!
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