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本帖最后由 ce958www 于 2021-2-22 16:55 编辑
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7 Y- R7 F# b) I' }, Y麻烦大神帮忙看看这个错误提醒要怎么修改?非常感谢!% v" J+ ^ K i0 q2 |
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错误使用 Idletime (line 37): m" K* V) j8 S2 x r. c" h
在 'Difference' 的工作进程上引发了 UndefinedFunction 错误。这可能是因为在这些工作进程上无法访问包含 'Difference' 的文件。使用' W* Q: O5 @$ d* ^! N4 J! y
addAttachedFiles(pool, files) 指定要附加的必要文件。请参阅 'parallel.Pool/addAttachedFiles'的相关文档以获取更多详细信息。0 x$ }) q/ v/ _; J
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) v' R1 I! y$ N2 C6 y出错 IDLETIME_NEH_PR_LJP (line 7)2 X6 T+ d9 {: ]% _1 B( `. @+ I* \
paRFor qq = 1:1200 g! n+ q, ?. R. N z* X/ M
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6 q$ K5 d4 @1 q: R! u% t: ]$ h原因:+ p" [' k6 _4 f! p
未定义与 'double' 类型的输入参数相对应的函数 'Difference'。# g8 l9 v+ O; D1 N, s: x
" O( k, M: P$ S0 T% S# G代码如下:. F3 Z9 t6 p5 }/ d
1 ?1 F& H- _6 w% U" J9 Xfunction [OUTPUT,OUTPUTTIME]=IDLETIME_NEH_PR_LJP! a5 h4 f* Q, M
% Take idle time as objective when insert new job to partial sequence# z% k6 m$ ^' [# }; l( y% W% K; H3 s
% martix including job operation time, n jobs and m machines6 H4 c# x- {* t) B; y- S' ?
%
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8 D9 \% m( d& `; A( n; h%% read data from excel
% r5 M/ c' \1 J3 A1 Z$ Y& {4 nparfor qq = 1:120
4 n1 x" N( f. s0 u, Lfilename='';
4 V4 I9 i2 A- n$ Y- {- \/ Ffilename=strcat(filename,'Taillard\');& `# U4 _! C7 S
filename=strcat(filename,num2str(qq));
; i* M9 L2 J( l& afilename=strcat(filename,'.txt');2 _. [( l. v5 ~! ^/ d: H& {8 j
[A]=load(filename,'%*s%n');/ Z5 e& E. ~6 d8 ~) q, Q1 [
T=A(:,2:2:end);
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%% input variables
/ d: {9 [/ G- R1 s5 u P* k2 h[n,m]=size(T);
$ G9 `1 i- F3 `Finalsequ=zeros(1,n);
. f9 @7 e; R3 I& L. p J+ @- gH=zeros(n,m);
, g. A8 o' K2 US=sum(T,2);! t2 d# S, V2 Q- M% X. c# V
M=[];
; ^4 c8 A$ i: e) wHH=[];. p: L0 _2 f3 B; }2 C! q7 G
SSequ=[];* o$ T v, L g( Z4 v, _
Sequ=[];
+ } Y! \; X' K& XTOTALIDLE=0;+ R4 o0 ~% u' U+ A k
AVG=[];
+ Y8 s% W0 p! j) x lDEV=[];
, j ]) ], ?3 y5 L# R8 X7 qSU=[];
- M T9 T: T% S4 a3 ?SUM=[];2 V5 n5 ]+ }! o( {, B
%% Obtain the initial sequence
% r, N5 F+ w) i( s% y) afor i=1:n
% T! D: Z) U1 s6 f2 r% O AVG(i)=mean(T(i,: ));
( @6 _' P/ Z* N; r% o DEV(i)=std(T(i,: ));
7 a( d% |# Y" o for j=1:m
6 ?! m. J6 P( J8 _ SU(j)=abs(T(i,j)-AVG(i));1 q5 Z8 `7 Q6 M, e: f/ W
end
L7 \' S; l* H, G% w' p SUM(i)=AVG(i)+mean(SU(: ))+abs(nthroot(skewness(T(i,: )),3))+1/kurtosis(T(i,: ))^(1/4);
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[a,b]=sort(SUM,2,'descend');* r) t b @1 e
%% NEH-INSERTION7 \+ L3 f9 H( Y8 c6 z" Z" J
% choose first two jobs
+ r* ?( T. D7 Z G ]# w. X, wH(1,: )=T(b(1),: ); % let the job with largest sum of processing times be the first job
$ w' }* J. b+ Y# KH(2,: )=T(b(2),: );
/ e6 A+ ~2 K6 e# ~: ^/ ~0 E7 uSequ(1)=b(1);' J) R/ H, t) D3 M) n5 y! u$ d
Sequ(2)=b(2); G% }/ {+ G5 N+ X6 q
TSequ=1:n;
8 @& B4 S$ O% vProfile=zeros(1,m-1);9 p$ z) X# R8 X3 _; @& x
[TOTALIDLE1,NProfile]=Idletime(H,2,TSequ(1),TSequ(2),Profile); %#ok<*NASGU,*ASGLU>; U3 `* E/ n4 J4 m: A
ttt1=TOTALIDLE1;
5 C7 Q) E7 [, EH(1,: )=T(b(2),: ); % let the job with the second largest sum of processing times be the first job) [, o4 p' S; Z% J0 `$ E' M
H(2,: )=T(b(1),: );. O" g7 U( B5 E) A6 y
Sequ(1)=b(2);
) @; g: S J c/ A! X" H# \Sequ(2)=b(1);
4 H! p2 v1 q$ w9 m4 H8 p) yProfile=zeros(1,m-1);. ?8 }: n- |6 A8 V
[TOTALIDLE4,NProfile]=Idletime(H,2,TSequ(1),TSequ(2),Profile); %#ok<*NASGU,*ASGLU>6 K. C8 e) r3 c1 {
ttt2=TOTALIDLE4;- B6 S$ G B0 I8 R) X
if ttt1<ttt2 % compare the makespan." z+ t. z: B5 m7 P9 Q0 a
H(1,: )=T(b(1),: );# N9 d1 u( j1 w( l, x; K5 _7 r
H(2,: )=T(b(2),: );
$ `7 }- n5 R! f' U7 {, I, | Sequ(1,1)=b(1);
3 S: H' N1 U* W7 s2 p% s7 a Sequ(1,2)=b(2);* Z* _' g2 h9 |8 T
TTT=ttt1; %#ok<*NASGU>$ R: y3 P* b; _; `8 g$ G
else' H8 }2 b# z$ }- y
H(1,: )=T(b(2),: );3 b* t/ Z, e6 P5 [ M/ h" ^
H(2,: )=T(b(1),: );3 L/ |9 I% E6 O: k I4 t
Sequ(1)=b(2);8 d! I2 v" ^( ^4 w- L7 Q
Sequ(2)=b(1);; _/ L* w Z7 A {' f7 l" }
TTT=ttt2;
3 i8 \7 ^7 w) P. P. {end/ ~. i+ M2 K+ i! [2 ?* \
% choose the subsequent job and add to the partial sequence* \! P% @( R' f7 @+ c( j
e=zeros(n+2,m+2);) h7 ]! O/ C3 q4 K6 ?+ g/ H) }
q=zeros(n+2,m+2);9 ~7 f8 Q T1 I! }
f=zeros(n+2,m+2);
( |# C2 n9 D. J2 VSSequ=Sequ;
, E2 \+ j* \: E$ |5 H( X Q* J2 J0 cfor i=3:n % insert the rest of jobs
4 T( |) B v3 @2 s' P {" S+ w( W& | Sequ=SSequ;* _8 r% n! |+ L2 \2 H
for d=1:i-1 % calculate earliest complection time of each job on the sequence
7 B! J4 v' c! X- i! z# _/ K" @ for y=2:m+1 1 W% s& D% d$ b# g" B* ^3 I
e(1,: )=0; % machine number starts from 2 to m+16 a: u5 M3 w+ l, ]: s; Z, | M/ m
e( :,1)=0;
' o; C- G' X5 W+ d' g9 K e(d+1,y)=max(e(d+1,y-1),e(d,y))+T(Sequ(d),y-1);* B1 N+ y7 o4 |7 P- A, D
end
3 `" K) S% i5 N! ] end
; _7 G* {4 j9 \. N- o3 l/ s for x=1:i % x indicates the position where the new job is going to be inserted) j$ u+ f( c, [- e
TSequ=Sequ;
+ O1 v3 X6 d- | t=e; Y- R D* V9 k5 f' N6 \
+ X* q) z# D5 p: T3 J for p=i-1:-1:x
8 w# V3 c+ x5 i, P8 j; U+ ?$ B TSequ(1,p+1)=TSequ(1,p);9 D3 M; Y% h1 n: E* k5 W
end" e1 H9 C8 c6 [* I% G
TSequ(1,x)=b(i);
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for p=x:i-16 ~* I/ o1 r- ]" _! E. e* K
for y=2:m+18 D3 b( ~* d4 H8 L% ?1 E
t(1,: )=0; % machine number starts from 2 to m+16 O' K7 C! i& c, J. Z
t( :,1)=0;( m# O; q( M7 g0 S0 j! l
t(x+1,y)=max(t(x+1,y-1),t(x,y))+T(b(i),y-1);
5 N3 D" G$ w$ k; g) h1 n t(p+2,y)=max(t(p+2,y-1),t(p+1,y))+T(TSequ(p+1),y-1);3 v8 F. K4 D- c0 ?! e4 Q8 A
end
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0 M8 F1 n+ I; M! ? for y=2:m+12 Y( c, d6 F- D
t(1,: )=0; % machine number starts from 2 to m+1
" C' q; w& `7 b: W* X t( :,1)=0;
$ L0 f4 Z( j6 S2 `1 I t(x+1,y)=max(t(x+1,y-1),t(x,y))+T(b(i),y-1);
' l$ c% c( I; P* r end
8 a: ]$ q1 i0 V* M: [ it=zeros(i+1,m+1);
; j3 h3 c' K4 v% r for d=1:i % computate idletimie martrix
T3 Y8 I! Z# |5 y5 |6 B( _# i' h for y=2:m+1
4 A2 x7 n1 `8 v& Z# l8 _1 U5 f it(1,: )=0;+ ~, W; u! C$ z5 V$ t
it( :,1)=0;. U% E8 D4 v: p! o# D( B
it(2,: )=0;
7 ]4 o) I }' q, h, o it(d+1,y)=max(0,t(d+1,y-1)-t(d,y));. S6 v2 l& i9 e" [. l. S: V# w4 _
end
' p' \7 x' b/ Y( Y+ ], V4 ^9 t end
, @5 P/ ~' Q2 L if x==1+ F2 m) S+ B, K
TOTALIDLE=sum(it(: ));
1 N7 R2 T# ~. U$ y Finalsequ=TSequ;4 H0 E) ]: `+ j6 i' p6 N Y/ f( K
end $ @$ O8 F2 u9 r0 J* ~
if sum(it(: ))<TOTALIDLE
1 d1 y5 b- A7 n" G5 j, k TOTALIDLE=sum(it(: ));" x6 ]5 f* K! ~# o* T
Finalsequ=TSequ;
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end7 S% z; S3 ^( m
SSequ=Finalsequ;
M ?) e" x! q. m4 @" vend
2 q5 p9 e' }2 h8 l* R/ N%% WRITE DATE INTO EXCEL
[2 \4 ^7 C* htime=toc;* C+ L8 }: n e5 B4 l2 [
time7 t+ p& d" t( F8 o$ e
OUTPUT(qq,1)=TOTALIDLE;
! N0 N3 B' E7 p7 x' F/ xOUTPUTTIME(qq,1)=time;% Y) V0 e( ?5 [: B
end) I2 u7 L: m$ d
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