了解一下C语言字符串的拆分函数strtok

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char *  strtok ( char * string, const char * delimiters );

- B3 ]; a; I; J9 I' ?% USequentially truncate string if delimiter is found.
  If string is not NULL, the function scans string for the first occurrence of any character included in delimiters. If it is found, the function overwrites the delimiter in string by a null-character and returns a pointer to the token, i.e. the part of the scanned string previous to the delimiter.
1 v( R9 \2 S% Q. Y2 {% G  After a first call to strtok, the function may be called with NULL as string parameter, and it will follow by where the last call to strtok found a delimiter.
4 U' d% \8 e) u7 u  delimiters may vary from a call to another.

Parameters.

string
0 _1 L2 o4 P8 C3 d3 E! d& pNull-terminated string to scan.
; U! D: ~2 v7 {# i) e4 oseparator
Null-terminated string containing the separators.
Return Value.
/ A( Y. f% o4 l9 G  A pointer to the last token found in string.   NULL is returned when there are no more tokens to be found.

# H. d+ s* F, ]4 cPortability.
  Defined in ANSI-C.
8 K# B3 R; _6 X" A3 z
/ y" n" Z' _. d7 h$ m1 J- vExample.

$ O7 E8 Y& y+ w. U) ~/* strtok example */
#include <stdio.h>
#include <string.h>
6 ?+ Q0 k' y1 c4 O7 G- h- q
/ S% ?$ G4 C$ H. rint main ()
; A" _' t7 j  e) ?, p{
  char str[] ="This is a sample string,just testing.";
0 o% O# I5 P6 L  g6 n7 |) P4 R  char * pch;
  printf ("Splitting string \"%s\" in tokens:\n",str);
( l, Y9 f# D5 ]3 E+ q7 c  pch = strtok (str," ");
) r3 w) w5 U4 u, M: A# |  while (pch != NULL)
  {
    printf ("%s\n",pch);
    pch = strtok (NULL, " ,.");
  }
  return 0;
7 `# s5 [7 O* q& A/ }" G}
Output:
" f2 k+ q& o; fSplitting string "This is a sample string,just testing." in tokens:
This
4 ]+ X7 H+ i' c  Jis
a
sample
' d, Z0 o4 G  r. p. I& g# W" `string
just
- b! z" k2 u+ @4 H  r9 o+ h5 e) vtesting

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了解一下C语言字符串的拆分函数strtok