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PCB线宽与电流(PCB line width and current)

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发表于 2020-2-17 15:30 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式

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PCB 线宽与电流(PCB line width and current)
1 I0 h+ `: M1 b( Y6 k  S' cThe withstand current of 1 square copper wire is 5 -- 8A, 380V can& w4 V, e+ w) @( C
be brought with maximum 4KW, 220V can be maximum 2KW.) W. u5 f! y+ `- \" ~, h" X
2 square? Three square meters can be pushed like that
4 ]% ^6 ~4 g, }( MPCB line width and current relationship
) `6 v# e& W, C# Q( ~4 _& d  i2 E: [4 Q" nI. calculation method is as follows:( g- f: D& {4 c9 i
First, the section area of Track is calculated. The copper foil; [. Y% P/ P* K, s* l
thickness of most PCB is 35um (the PCB manufacturer can be asked if it# K) Y* l% b& D9 N
is not certain). The width of the PCB is the% t: O5 Z2 @: M
cross-sectional area. There is an experience value of current
8 U6 k% T8 p7 d6 ddensity for 15 ~ 25 amperes per square millimeter. We can just call it  |* }, O' c; U- w, s; u+ N$ P
the area where we get the volume.2 t, l# O1 O3 P4 k: V
I = KT0.44 A0.75 (K is the correction factor, which is 0.024 in the0 j# s* Q6 p* n; e3 W( H
inner layer of the copper line, and 0.048 in the outer layer)8 w8 _  _1 L" L) J0 a% j
T to the maximum temperature rise, the unit for degrees Celsius
3 ?+ G/ L0 i( g3 L% U/ f% N(copper melting point is 1060 ?)  X( p% N* V7 X3 c6 q3 M
A to cover the area of copper, the unit is square MIL (not mm mm,* N6 `5 D' x( R! n5 C% V% x/ U
the attention is square MIL.)+ I5 d; _* u5 S- q! {
I is the maximum allowable current, the unit is ampere (amp)./ y, u% @& `/ K  i# A7 `
The average 10mil = 0.010 inch = 0.254 May be 1A, 250MIL = 6.35mm,8 o- D- o% j/ H% L" z
which is 8.3 A  
0 ?- c# m! x' M& q/ i4 \: J3 P' L' m+ w( l9 v1 ~
' s0 P$ Z- w0 b9 p. h6 a  a4 [3 }

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2#
发表于 2020-2-26 14:30 | 只看该作者
PCB线宽与电流

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3#
发表于 2020-3-3 14:24 | 只看该作者
学习一下,谢谢。
( C: o: R' e+ f4 n2 ]/ T, @1 f
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