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PCB 线宽与电流(PCB line width and current)
$ z: T$ ]; X5 X) QThe withstand current of 1 square copper wire is 5 -- 8A, 380V can- n4 y' Q$ }/ `5 {
be brought with maximum 4KW, 220V can be maximum 2KW.
+ E8 _( v$ G: t2 square? Three square meters can be pushed like that
]+ m2 q* S% b1 v: R8 c! M% E7 NPCB line width and current relationship& \; C; j* t* t+ T7 M
I. calculation method is as follows:/ J& Q! N+ \* m
First, the section area of Track is calculated. The copper foil: \8 b) f6 Z8 ]$ i0 y
thickness of most PCB is 35um (the PCB manufacturer can be asked if it
0 r/ k" i* n# O+ N* I! g, @. Mis not certain). The width of the PCB is the
4 h* ~9 ^" C6 h3 @. A- ucross-sectional area. There is an experience value of current
" ?# w+ G# k( \/ z4 `density for 15 ~ 25 amperes per square millimeter. We can just call it
3 X. v8 n5 `; d: A/ C Gthe area where we get the volume.: I1 u; s% q! F: l; F
I = KT0.44 A0.75 (K is the correction factor, which is 0.024 in the
' k* D& o7 h3 C. g, M+ O( t6 C. b1 sinner layer of the copper line, and 0.048 in the outer layer)
) K# f$ _: Z! P9 V. ST to the maximum temperature rise, the unit for degrees Celsius
- W, @. I3 s6 {0 k(copper melting point is 1060 ?). c4 S7 M1 _" s2 w3 \- q
A to cover the area of copper, the unit is square MIL (not mm mm,
: R+ \2 Q- U6 j' [9 q. fthe attention is square MIL.)) w% M) W% n% }- [. q3 r* F7 I6 o
I is the maximum allowable current, the unit is ampere (amp).
8 \3 g( v7 P. Z3 T4 dThe average 10mil = 0.010 inch = 0.254 May be 1A, 250MIL = 6.35mm,7 ^: Q9 Y' u; Y
which is 8.3 A " S5 O! u0 {3 s& i! `/ w
/ c4 }0 S# z) F% l8 C- ^$ U" e8 C3 }' v8 y1 `' q7 L+ a$ e
& r* b/ z6 y0 H2 v6 e
/ m# l& z8 E- H |
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